Multiplying

For instance, in the problem below, the degree of the denominator is 2, so multiplying by

12
x1--                           which is really ‘1’
x2
is tantamount to dividing each term in the numerator and denominator by x2:
                                                    2
    1---2x2-+-x        1--2x2-+-x- x12-       x12---2xx2-+-xx2-
lxim→∞    x2 - 4   = lxi→m∞    x2 - 4   ⋅-1 = xli→m∞    x2-  4-
                                   x2           x2   x2

Return to the general computation page.

Return to the Special Challenges page.

Return to the Limits at Infinity page.